F=INt 10/x^2 dx -INT 2/x^6 dx
= -10/x +2/5 * x^-5+c
F(1)=0=-10+2/5 _+ C solve for c.
7) Consider the function f(x)=(10/x^2)−(2/x^6). Let F(x) be the antiderivative of f(x) with F(1)=0.
Then F(x)= ?
2 answers
F' = 10 x^-2 dx - 2 x^-6 dx
F = -10x^-1 + (2/5) x^-5 + c
when x = 1 , F = 0
0 = -10 + 2/5 + c
c = 48/5
F = -10 /x + 2/(5x^5) +48/5
F = -10x^-1 + (2/5) x^-5 + c
when x = 1 , F = 0
0 = -10 + 2/5 + c
c = 48/5
F = -10 /x + 2/(5x^5) +48/5