What’s a function that has a vertical asymptote at x= -2, a horizontal axis at y= 3, and a hole at (4,2)?

Answer 1

vertical asymptote at x= -2
y = 1/(x+2)
horizontal asymptote at y = 3 ... degree top and bottom must be the same
y = 3x/(x+2)
A hole at (4,2) means that we're trying to divide by x-4, so
y = 3x(x-4) / (x+2)(x-4)