Asked by Karen

An airplane flew 300 miles at a bearing of N65°E from airport A to airport B. The plane then flew at a bearing of S38°E to airport C. Find the distance from A to C if the bearing from airport A to airport C is S60°E.
Answered by Reiny
Did you make your sketch?
Mine is triangle ABC with
angle A = 55°
angle C = 22°, and
angle B + 103°

then it is just a matter of the sine law:
AC/sin103 = 300/sin22
I got AC = appr 780 miles
Answered by gift
The bearing of town P and Q is 315°, while town R is south of town P and west of town Q. if town R is 60km away from town Q, how far is town R to from town P
Answered by value
what an air craft is flying from certain airfield 15 degree north and 105 east to 15 north and 45 degree west calculate the distance moved by the plane.
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