An airplane flew 300 miles at a bearing of N65°E from airport A to airport B. The plane then flew at a bearing of S38°E to airport C. Find the distance from A to C if the bearing from airport A to airport C is S60°E.

Answer 1

Did you make your sketch?
Mine is triangle ABC with
angle A = 55°
angle C = 22°, and
angle B + 103°

then it is just a matter of the sine law:
AC/sin103 = 300/sin22
I got AC = appr 780 miles

Answer 2

The bearing of town P and Q is 315°, while town R is south of town P and west of town Q. if town R is 60km away from town Q, how far is town R to from town P

Answer 3

what an air craft is flying from certain airfield 15 degree north and 105 east to 15 north and 45 degree west calculate the distance moved by the plane.