Asked by Ice
A plane flew 150 miles on a course of 220 degrees and then 130 miles on a course of 130 degrees. Then the plane returned to it's starting point via the shortest route possible. Find that shortest distance.
Answers
Answered by
Steve
The individual displacements are
150 @ 220° = (-96.4,-114.9)
130 @ 130° = (99.6,-83.6)
So, the final location is at (3.2,-198.5)
Just find the distance from there to the origin.
150 @ 220° = (-96.4,-114.9)
130 @ 130° = (99.6,-83.6)
So, the final location is at (3.2,-198.5)
Just find the distance from there to the origin.
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