horizontal travel:
x = Vxt = v cos50° = 0.6428v t
.6428v t = 20.75
v = 32.2806/t
y = Vy t - 16t^2
= 0.7660v t - 16t^2
= 0.7660(32.2806/t)t - 16t^2
= 24.7270 - 16t^2
y=0 when t = 1.243
Vy (1.243) - 16(1.243^2) = 0
Vy = 19.89
SO,
y = 19.89t - 16t^2
Now just find the vertex of the parabola for max height.
No idea what the mud and subsidence have to do with anything.
Larry kicked a ball at a 50 degrees angle to a direction north. It travels a horizontal distance of 20ft 9inchs before hitting the ground .The ball travels exactly 1min 18 sec after hitting the ground.
The ball hit a mud and cause dthe ball to subside 2inches.
Question: how many meters is the peak height of the ball from the ground after it was hit to the current postion of the ball?
1 answer
1 answer