Question
A plane travels 1000 km at an angle of 40 degrees East to North, then changes direction and travels 500 km at an angle of 20 degrees North to East. What is the magnitude and direction of the planes total displacement?
Answers
Henry
40o E. to N. = 50o N. t0 E.
D = 1000km[50o] + 500km[20o].
X = 1000*Cos50 + 500*Cos20o =
Y = 100*sin50 + 500*sin20 =
Tan A = Y/X, A = ? = Direction.
X/Cos A = Magnitude.
D = 1000km[50o] + 500km[20o].
X = 1000*Cos50 + 500*Cos20o =
Y = 100*sin50 + 500*sin20 =
Tan A = Y/X, A = ? = Direction.
X/Cos A = Magnitude.