Question
plane 1 travels 600 mph. plane 2 travels 800 mph and leaves 45 minutes later. when will plane 2 pass plane 1
Not sure what formula I use.
Not sure what formula I use.
Answers
Steve
in 45 minutes, plane 1 has gone 450 miles.
Plane 2 goes 200 mi/hr faster, so it takes 450/200 = 2.25 hours to catch up.
Or, since distance = speed * time,
600(t+.75) = 800t
Plane 2 goes 200 mi/hr faster, so it takes 450/200 = 2.25 hours to catch up.
Or, since distance = speed * time,
600(t+.75) = 800t