Asked by Lance Gladbach
A soccer ball is kicked from the ground and lands 2.2 seconds later. If the ball was kicked at an angle of 55 degrees above horizontal, what was the ball's total initial speed?
Answers
Answered by
Arora
For an object in projectile motion,
Time of flight = t
Initial speed = u
Angle with horizontal = θ
g = acceleration due to gravity
t = (2*u*sinθ)/g
=> u = (t*g)/(2*sin55)
= (2.2*9.8)/(2*0.819)
= 13.16 m/s
Time of flight = t
Initial speed = u
Angle with horizontal = θ
g = acceleration due to gravity
t = (2*u*sinθ)/g
=> u = (t*g)/(2*sin55)
= (2.2*9.8)/(2*0.819)
= 13.16 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.