A soccer ball is kicked with a speed of 22m/s at an angle of 35.0º above the horizontal. Can someone show me how to find how long the ball was in the air if the ball lands at the same level from which it was kicked?

Answer 1

find the initial vertical velocity ... 22 m/s * sin(35º)

gravitational acceleration (g = 9.8 m/s^2) will slow the ball to a stop (vertically)
... the ball will then fall back down
... time up = time down

time = velocity / acceleration

flight time = 2 * [(initial vertical velocity) / g]

Answer 2

Vo = 22m/s[35o].
Yo = 22*sin35 = 12.62 m/s = Ver. component of initial velocity.

Y = Yo + g*Tr = 0 at max. ht.
12.62 + (-9.8)Tr = 0,
Tr = 1.29 s. = Rise time. = Fall time(Tf).

T = Tr + Tf = 1.29 + 1.29 =

0*Tr = 0,