Asked by Ashley
Limit as n goes to infinity of ((2n)!/(n^n)).
Answers
Answered by
Steve
n! is basically an nth-degree polynomial
(2n)! is a 2n-th degree polynomial
n^n is an nth-degree polynomial
so, (2n)!/n^n -> n^2n/n^n is like an nth-degree polynomial, and -> infinity
(2n)! is a 2n-th degree polynomial
n^n is an nth-degree polynomial
so, (2n)!/n^n -> n^2n/n^n is like an nth-degree polynomial, and -> infinity
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