Asked by Callie
                Find the limit as x->infinity of (1+8/x)^x
            
            
        Answers
                    Answered by
            Steve
            
    recall that
(1 + 1/x)^x --> e
and now let x=8u to get
(1+1/u)^8u = [(1+1/u)^u]^8 = e^8
    
(1 + 1/x)^x --> e
and now let x=8u to get
(1+1/u)^8u = [(1+1/u)^u]^8 = e^8
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