Asked by Callie
Find the limit as x->infinity of (1+8/x)^x
Answers
Answered by
Steve
recall that
(1 + 1/x)^x --> e
and now let x=8u to get
(1+1/u)^8u = [(1+1/u)^u]^8 = e^8
(1 + 1/x)^x --> e
and now let x=8u to get
(1+1/u)^8u = [(1+1/u)^u]^8 = e^8
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