Ask a New Question

Asked by Callie

Find the limit as x->infinity of (1+8/x)^x
9 years ago

Answers

Answered by Steve
recall that

(1 + 1/x)^x --> e

and now let x=8u to get

(1+1/u)^8u = [(1+1/u)^u]^8 = e^8
9 years ago

Related Questions

the limit from n->infinity of the summation of [2+(3/n)k]^2(3/n) when k=1 The limit from x--> infinity of x^(3/x) i keep getting 3/infinity, which is infinity and this ans... as x-> + infinity (limit) 3x^4-2x^2/x^4+5x^2 i got positive infinity. is this right Limit as n goes to infinity of ((2n)!/(n^n)). Find the limit as x->infinity of ((3x+2)/(3x+4))^(3x+1) Limit = x-->infinity 11x^5+4x^3-6x+2/6x^3+5x^2+3x-1 My work: After doing lots of work I got... limit x tends to infinity POW(x,x) limit x tends to infinity ( 1+root n)/(1-rootn) limit x tends to infinity, x(e-((x+2)/(x+1))^x) Dont know how to use power series
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use