Asked by Binoy kumar mahato
limit x tends to infinity ( 1+root n)/(1-rootn)
Answers
Answered by
Reiny
You must have meant:
lim (1 + √n)/(1-√n) as n ---->∞
divide top and bottom my √n
= lim (1/√n + 1)/(1/√n - 1) as n ---->∞
Now look at the 1/√n term
as as n ---->∞ , 1/√n -----> 0
e.g. let n = 10,000,000 , 1/√10,000,000 = .00031... getting small
So you are left with
lim (0 + 1)/(0 - 1) as n ---->∞
= -1
lim (1 + √n)/(1-√n) as n ---->∞
divide top and bottom my √n
= lim (1/√n + 1)/(1/√n - 1) as n ---->∞
Now look at the 1/√n term
as as n ---->∞ , 1/√n -----> 0
e.g. let n = 10,000,000 , 1/√10,000,000 = .00031... getting small
So you are left with
lim (0 + 1)/(0 - 1) as n ---->∞
= -1
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