Asked by Anonymous
a footbal is thrown at an angle of 35 reltive to the ground at a speed of 25m/s. the football is then caught 38m from the throwner. you can assume the height that the ball thrown at is the same as the height it was caught. how long was the football in the air ?
Answers
Answered by
Henry
Vo = 25m/s @ 35o
Xo = 25*cos35 = 20.48 m/s.
Dx = Xo*t = 38 m.
t = 38/Xo = 38/20.48 = 1.86 s.
Xo = 25*cos35 = 20.48 m/s.
Dx = Xo*t = 38 m.
t = 38/Xo = 38/20.48 = 1.86 s.