Asked by Anonymous
A body is thrown at an angle 30 to the horizontal with the velocity of 30m/s.After 1 second,its velocity will be
Answers
Answered by
Damon
v = velocity up = 30 sin 30 - 9.81 t
u = velocity horizontal = 30 cos t
if t = 1
v = 15 - 9.81
u = 30(.866)
speed = sqrt (u^2+v^2)
tan angle up = v/u
u = velocity horizontal = 30 cos t
if t = 1
v = 15 - 9.81
u = 30(.866)
speed = sqrt (u^2+v^2)
tan angle up = v/u
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