Question

a body is thrown a point with speed 50m/s at an angle 37 degree with horizontal. when it has moved a horizontal distance of 80 m then it's distance from point of projection

Answer 1

horizontal speed = u = 50 cos 37

t = 80/u

then how high is it at t
h = (50 sin 37) t - 4.9 t^2

then
d = sqrt (80^2 + h^2)