A ball is thrown at an angle of 45 degrees to the ground. If the ball lands 90 m away, what is the initial speed of the ball?

1 answer

Dx = Vo^2*sin(2A)/g = 90 m.
Vo^2*sin90 / 9.8 = 90.
Vo^2*0.102 = 90.
Vo^2 = 90 / 0.102 = 882.
Vo = 29.7 m/s.