Asked by Anonymous
A ball is thrown at an angle of 45 degrees to the ground. If the ball lands 90 m away, what is the initial speed of the ball?
Answers
Answered by
Henry
Dx = Vo^2*sin(2A)/g = 90 m.
Vo^2*sin90 / 9.8 = 90.
Vo^2*0.102 = 90.
Vo^2 = 90 / 0.102 = 882.
Vo = 29.7 m/s.
Vo^2*sin90 / 9.8 = 90.
Vo^2*0.102 = 90.
Vo^2 = 90 / 0.102 = 882.
Vo = 29.7 m/s.
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