Asked by Mary

Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. At what time t does the ball stop going up and start returning to earth?
Answered by bobpursley
you are given h(t), to you need to take the derivatave of h'(t) and set it to zero.
The derivative of height is velocity.

Answered by Mary
Ohhhhhhhhhhhhhhhhhhhhh, Thanks!
Answered by bobpursely hater
37 - 32(3.2) = -65.4
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