Asked by Mary
Suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t – 16t2, where h is in feet and t is in seconds. At what time t does the ball stop going up and start returning to earth?
Answers
Answered by
bobpursley
you are given h(t), to you need to take the derivatave of h'(t) and set it to zero.
The derivative of height is velocity.
The derivative of height is velocity.
Answered by
Mary
Ohhhhhhhhhhhhhhhhhhhhh, Thanks!
Answered by
bobpursely hater
37 - 32(3.2) = -65.4
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