Asked by nate
A 0.73 kg ball is thrown straight up with an initial velocity of 2.50 m/s. Taking the potential energy of gravity to be zero at the height from which the ball is thrown, determine its gravitational potential energy at the balls highest point. Ignore air resistance.
Answers
Answered by
Elena
PE= ΔKE
mgh = mv²/2=0.73•2.5²/2= …
mgh = mv²/2=0.73•2.5²/2= …
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