Question

A mass pulled by a constant force accelerates from 10 cm/s to 40 cm/s in 5.5 s. A second force accelerates the same mass from rest to 105 cm/s in 15.0 s. If the first force is known to be 5.0 N, that what is the magnitude of the second force?

Answer 1

a1=(V-Vo)/t = (0.4-0.1)/5.5=0.055 m/s^2

a2 = (V-Vo)/t = (1.05-0)/15 = 0.07 m/s^2

F2=(a2/a1)*5N. = (0.07/0.055)*5N. = 6.36 N.