Asked by Ked
A horizontal force of 3,000,000 dynes can keep a 50 kg mass in uniform motion. What is the coefficient of the kinetic friction? At what angle must the plane be tilted to allow the mass to slide?
Answers
Answered by
bobpursley
friction=mu(mg)
3E8dynes*1E-5N/dyne=mu*50*g
solve for mu, the coefficent of friction.
Now on a tilt:
force gravity down the plane: mgSinTheta
force normal to the plane: mgCosTheta
friction force=mu*force normal
so if you tilt it to sliding,
forcedownplane=friction
mgsinTheta=mu*mgCosTheta
tanTheta=mu
theta=arctan mu
3E8dynes*1E-5N/dyne=mu*50*g
solve for mu, the coefficent of friction.
Now on a tilt:
force gravity down the plane: mgSinTheta
force normal to the plane: mgCosTheta
friction force=mu*force normal
so if you tilt it to sliding,
forcedownplane=friction
mgsinTheta=mu*mgCosTheta
tanTheta=mu
theta=arctan mu
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.