Asked by Anonymous

A horizontal force of 804 N is needed to drag a crate across a horizontal floor with a constant speed. You drag the crate using a rope held at an angle of 32° (from the horizontal).
(a) What force do you exert on the rope?
1 N
(b) How much work do you do on the crate if you move it 22 m?
2 J
(c) If you complete the job in 8.0 s, what power is developed?
3 kW
Answered by Henry
a. Fe*cos32 = 804 N.
Fe = 804 / cos32 = 948 N. = Force exerted.

b. W = Fe * d = 948 * 22 = 20,856 J.

c. P = W / t = 20,656 / 8 s. = 2607 J/s
= 2607 Watts = 2.607 KW.
Answered by khaled
A. is correct but B. and C. is incorrect trust me....
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