Asked by Jabrika
A horizontal force of 24 N is being applied to a box on a level surface. The box is accelerating at the rate of2280889against a frictional force of 14 N. What is the mass of the box?
Answers
Answered by
Henry
Fap = 24 N. = Force applied.
a = 2.28 m/s^2?
Fk = 14 N.
(Fap-Fk) = M*a
M = (Fap-Fk)/a = (24-14)/2.28 = 4.39 kg.
= Mass of the box.
a = 2.28 m/s^2?
Fk = 14 N.
(Fap-Fk) = M*a
M = (Fap-Fk)/a = (24-14)/2.28 = 4.39 kg.
= Mass of the box.
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