Fap = 24 N. = Force applied.
a = 2.28 m/s^2?
Fk = 14 N.
(Fap-Fk) = M*a
M = (Fap-Fk)/a = (24-14)/2.28 = 4.39 kg.
= Mass of the box.
a = 2.28 m/s^2?
Fk = 14 N.
(Fap-Fk) = M*a
M = (Fap-Fk)/a = (24-14)/2.28 = 4.39 kg.
= Mass of the box.
According to the problem, a horizontal force of 24 N is being applied to the box, and it is accelerating at a rate of 2.28 m/s^2 against a frictional force of 14 N. Let's denote the mass of the box as 'm'.
The force acting on the box is the applied force minus the frictional force:
Force = Applied force - Frictional force
= 24 N - 14 N
= 10 N
Now, according to Newton's second law, the force acting on the box is equal to the mass of the box multiplied by its acceleration:
Force = mass Ć acceleration
10 N = m Ć 2.28 m/s^2
To find the mass 'm', we need to rearrange the equation:
m = Force / acceleration
= 10 N / 2.28 m/s^2
ā 4.38 kg
Therefore, the mass of the box is approximately 4.38 kg.
F = m * a
Given:
Force (F) = 24 N (applied force)
Frictional force (f) = 14 N
Acceleration (a) = 2.280889 m/s^2
We can subtract the frictional force from the applied force to find the net force:
Net force = 24 N - 14 N
Net force = 10 N
Now, we can rearrange the equation to solve for the mass (m):
m = F / a
Substituting the values:
m = 10 N / 2.280889 m/s^2
m ā 4.38 kg
Therefore, the mass of the box is approximately 4.38 kg.