A box is being accelerated across a rough, level surface. A force is being applied to the box in an upward and a rightward direction (as shown below). This force makes an angle of 30 degrees with the horizontal. The force of friction experienced by box would be equal to______.

asked by anonmous

8 years ago

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1 answer

Fn = M*g-F*sin30 = Normal force.

Fk = uk * Fn = uk*(M*g-F*sin30).

answered by Henry

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Question

A box is being accelerated across a rough, level surface. A force is being applied to the box in an upward and a rightward direction (as shown below). This force makes an angle of 30 degrees with the horizontal. The force of friction experienced by box would be equal to______.

1 answer

Fn = M*g-F*sin30 = Normal force.

Fk = uk * Fn = uk*(M*g-F*sin30).

Henry · Answer

Fn = M*g-F*sin30 = Normal force. Fk = uk * Fn = uk*(M*g-F*sin30).