Question
A 75kg box is being pulled across the floor with a force of 465N.If the kinetic coefficient of friction is 0.57,what is the acceleration of the box?
Answers
drwls
Box weight = m g = 735 N
Friction force = 0.57*735 = 419 N
net force = Fnet = 465 - 419 = 46 N
acceleration = Fnet/m = 46/75
= 0.613 m/s^2
Friction force = 0.57*735 = 419 N
net force = Fnet = 465 - 419 = 46 N
acceleration = Fnet/m = 46/75
= 0.613 m/s^2