Asked by hy
a 18.0kg sled being pulled across horizontal surface at constant velocity. pulling force has magnitude of 82.0N and is directed at angle of 30 degree above horizontal. determine coefficient of kinetic friction
Answers
Answered by
drwls
Uk = (friction force)/(normal force)
at constant velocity
The friction force is the horizontal component of the twowing force.
Uk = (82 cos30)/(Mg - 82 sin 30)
= 71.1/(176.4 - 41.0) = 0.525
at constant velocity
The friction force is the horizontal component of the twowing force.
Uk = (82 cos30)/(Mg - 82 sin 30)
= 71.1/(176.4 - 41.0) = 0.525
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.