Asked by Anonymous
A 9 v battery is connected across a series combination of 100 W, 35 W, and 55 W resistors. The current measured in the circuit is 100 mA. What can be wrong in this circuit?
Answers
Answered by
Elena
W = Watt (unit of power)
Resistance: Ohm =Ω =>
total resistamce
R=100 Ω+35 Ω+55 Ω=190 Ω
According to Ohm's Law
ℰ=IR =100•10⁻³•190 =19 V ≠ 9 V.
Resistance: Ohm =Ω =>
total resistamce
R=100 Ω+35 Ω+55 Ω=190 Ω
According to Ohm's Law
ℰ=IR =100•10⁻³•190 =19 V ≠ 9 V.
Answered by
Adam
thank you for answering my question. i need to find out why it is only outputing 100mA current only
100 W resistor is open.
100 W resistor is shorted.
35 W resistor is shorted.
55 W resistor is shorted.
100 W resistor is open.
100 W resistor is shorted.
35 W resistor is shorted.
55 W resistor is shorted.
Answered by
Elena
An open resistor is a resistor with one of the leads not connected.An open resistor can have no current or voltage, and it can have no effect on any circuit. =>
35 Ω and 55 Ω are shorted and 100 Ω is open =>
ℰ=IR =100•10⁻³• 90 = 9 V.
35 Ω and 55 Ω are shorted and 100 Ω is open =>
ℰ=IR =100•10⁻³• 90 = 9 V.
Answered by
Adam
Thank you Elena, you are a big help.
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