Asked by ari
A net horizontal force F =A +Bt^3 acts on a 2kg object, where A = 5N and B = 2N/s3. What is the horizontal velocity of this object 4.0 seconds after it starts from rest?
F=ma=5+2t^3
a=2.5+t^3
V=2.5t+(1/4)(t^3)
therefore, at t=4, V=74m/s
Is this correct?
F=ma=5+2t^3
a=2.5+t^3
V=2.5t+(1/4)(t^3)
therefore, at t=4, V=74m/s
Is this correct?
Answers
Answered by
macro1134
V=2.5t+t^4
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