Asked by PAT
CASHIER HAS A TOTAL OF 39 BILLS CONSISTING OF ONES, FIVES, AND TWENTIES. THE NUMBER OF TWENTIES IS 16 LESS THAN THE NUMBER OF ONES. THE TOTAL VALUE IS $208. HOW MANY OF EACH DENOMINATION IS THERE.
Answers
Answered by
Steve
Just list the facts as given:
u+f+t = 39
t = u-16
u+5f+20t = 208
Now just solve as usual
u+f+t = 39
t = u-16
u+5f+20t = 208
Now just solve as usual
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