Asked by Judith

A cashier has 26 bills consisting of three times as many ones as fives, one less ten than fives, and the rest twenties. If the value is $120, find how many of each she has.
Answered by Damon
x fives
3x ones
(x-1) tens
sum so far = (4x-1)
[26 - (4x-1)] twenties = (27-4x)

3x + 5x + 10(x-1) + 20(27-x) = 120

proceed :)
Answered by Olivia
3f is the number of ones
f-1 is the number of ten
rest is 20s
total is 120
break down the problem and write what you know.
120=3f+f-1, the rest is 20s.
120=4f rest is 20s
4 times five is 20
20+ the rest is twenties=120
-20 -20
the rest are 20s=100
100/20=5 there are five 20s. You do the rest.
Answered by Anonymous
Damon, I have the answers but don't know how to get the equation. Ones - 15; Fives - 5; Tens - 4; Twenties - 2. I don't get that answer with your equation. Do you mind looking at it again?
Answered by Anonymous
Thank you for your help. It's much appreciated.
Answered by Anonymous
3x+5x+10(x-1)+20(27-x)=120
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