Asked by keitha
A cashier has a total of 126 bills, made up of fives and tens. The total value of money is $890. How many ten-dollar bills does the cashier have?
Answers
Answered by
bobpursley
5F+10T=890
F+T=126
multiply the second equation by 5, then subtract the equation from the first.
5F+10T=890
5F+5T=630
then subtract equations
5T=360
T=72
check all that.
F+T=126
multiply the second equation by 5, then subtract the equation from the first.
5F+10T=890
5F+5T=630
then subtract equations
5T=360
T=72
check all that.
Answered by
Afeez
Let the fives and tens be represented by 5x +10y=890, x +y =126 solve by elimination . X =74.. y =52
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