Asked by Dustin
A cashier has a total of 37 bills consisting of ones, fives and twenties. The number of twenties is 15 less than the number of ones. The total value of money is $191. How many of each denomination of bill are there?
There are ___ ones, ___fives, ____twenties.
There are ___ ones, ___fives, ____twenties.
Answers
Answered by
Reiny
number of ones --- x
number of twenties --- x-15
number of fives = 37 - x - (x-15) = 52 - 2x
x + 5(52-2x) + 20(x-15) = 191
solve for x, then sub back into my definitions.
number of twenties --- x-15
number of fives = 37 - x - (x-15) = 52 - 2x
x + 5(52-2x) + 20(x-15) = 191
solve for x, then sub back into my definitions.
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