Asked by serina
A spring is stretched by 0.72 m from its orginal length with an external force of 10.5. What is the spring constant, k, of the spring?
Answers
Answered by
Damon
F = k x
10.5 = k (.72
k = 10.5 N/.72 m
10.5 = k (.72
k = 10.5 N/.72 m
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