Asked by Osas
a spring is stretched 0.04m by a force of 15n. Calc the workdone by the force
Answers
Answered by
Anonymous
easy way:
average force= 15/2 = 7.5 N
7.5 N * 0.04 m = 0.3 Joules
hard way:
F= k x so k = 15/0.04 = 375 N/m
work = (1/2) k x^2 = (1/2) * 375 * 0.04^2 = 0.3 Joules but we knew that.
average force= 15/2 = 7.5 N
7.5 N * 0.04 m = 0.3 Joules
hard way:
F= k x so k = 15/0.04 = 375 N/m
work = (1/2) k x^2 = (1/2) * 375 * 0.04^2 = 0.3 Joules but we knew that.
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