Asked by chhaya
if a train travell at speed of 90km/hour. and when the break applied at 5m/sec2. how much it will travel before stoping
Answers
Answered by
MathMate
90 km/hour = 90/3.6=25 m/s
deceleration rate, a = 5 m/s²
time= 25/5
= 5 seconds
Must be a new braking system :)
deceleration rate, a = 5 m/s²
time= 25/5
= 5 seconds
Must be a new braking system :)
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