Question
the driver of the train travelling at 40m/s applies break as the train enters the station the train slow down at a rate of 2km/s square.the platform is 400m long.how long will the train take to slow down to rest?
Answers
a = 2m/s^2 ?.
t = (Vf - Vo) / a,
t = (0 - 40) / -2 = 20s.
t = (Vf - Vo) / a,
t = (0 - 40) / -2 = 20s.
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