Question

A train traveling at a speed of 110 km/h uniformly decelerates for 20 seconds. During that time it travels 450 m.

a. What is the acceleration ? = m/s2

b. What is its speed after the deceleration ? = km/h

Answer 1

s = v0*t + 1/2 at^2
plug in your numbers for v0 (convert to m/s) and t.

now, use that value of a for

v = v0 + at
and then convert m/s to km/hr