Asked by kd
A train traveling between two stations. The train starts from rest and accelerates uniformly for 150 seconds. It then travels at a constant speed for 300 seconds and finally decelerates uniformly for 200 seconds.
Given that the distance between the two stations is 10450 m, calculate the:
(a) Maximum speed, in km/h, the train attained;
(b) Acceleration,
(c) Distance the train traveled during the last 100 seconds;
(d) Time the train takes to travel the first half of the journey.
Given that the distance between the two stations is 10450 m, calculate the:
(a) Maximum speed, in km/h, the train attained;
(b) Acceleration,
(c) Distance the train traveled during the last 100 seconds;
(d) Time the train takes to travel the first half of the journey.
Answers
Answered by
oobleck
apply your basic equations of motion
v = at
s = v<sub><sub>0</sub></sub>t + 1/2 at^2
v = at
s = v<sub><sub>0</sub></sub>t + 1/2 at^2
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