Asked by Danny
1. A train traveling at a speed of 110km/h decelerates for 20 seconds. During that time it travels 450 meters.
A) What is the acceleration? = m/s^2
B) What is its speed after deceleration? = km/h
Initial velocity (u) = 110km/h
Time (t) = 20s
Distance = 450m
Using this formula s = ut + 1/2 at^2
I need some help. Thank you.
A) What is the acceleration? = m/s^2
B) What is its speed after deceleration? = km/h
Initial velocity (u) = 110km/h
Time (t) = 20s
Distance = 450m
Using this formula s = ut + 1/2 at^2
I need some help. Thank you.
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