Asked by Nick
Two people start from the same point. One walks east at 5 mi/h and the other walks northeast at 7 mi/h. How fast is the distance between the people changing after 15 minutes? (Round your answer to three decimal places.)
Answers
Answered by
Steve
At time t, using the law of cosines,
d^2 = (7t)^2 + (5t)^2 - 2(5t)(7t)cosπ/4
= 74t^2 - 35√2 t^2
= (74-35√2)t^2
so,
2d dd/dt = 2(74-35√2)t
Now, plug in your numbers to get d(15), and solve for dd/dt at t=15
Remember to use appropriate units
d^2 = (7t)^2 + (5t)^2 - 2(5t)(7t)cosπ/4
= 74t^2 - 35√2 t^2
= (74-35√2)t^2
so,
2d dd/dt = 2(74-35√2)t
Now, plug in your numbers to get d(15), and solve for dd/dt at t=15
Remember to use appropriate units
Answered by
john
17
Answered by
al
Two people start from the same point. One walks east at 6 mi/h and the other walks northeast at 8 mi/h. How fast is the distance between the people changing after 15 minutes? (Round your answer to three decimal places.)
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