Question

A car starts at rest then accelerates at a constant rate to 11.9 m/s in 10.0 seconds. It then slows to 1.5 m/s during the next 5.0 seconds. To the nearest hundredth of a m/s 2 , what is the average acceleration during the first 10.0 seconds?

Answer 1

a = (V-Vo)/t = (11.9-0)10 = 1.19 m/s^2.