Question
A car start from rest and accelerate uniformly until it reaches a velocity of 30m/s after 5sec .it travels with uniform velocity from 15sec and is then brought to rest in 10sec with a uniform retadiation determining
1.acceleration of the car
2.the retadiation
3.the distance cover after 5sec
4. the total distance cover
solve
1.acceleration of the car
2.the retadiation
3.the distance cover after 5sec
4. the total distance cover
solve
Answers
#1. 30m/s / 5sec = 6m/s^2
#2. twice the time, so -3m/s^2
#3. s = 1/2 at^2
#4. (1/2 * 6 * 5^2) + (30*15) + (30*10 - 1/2 * 3 * 10^2) = _____ m
#2. twice the time, so -3m/s^2
#3. s = 1/2 at^2
#4. (1/2 * 6 * 5^2) + (30*15) + (30*10 - 1/2 * 3 * 10^2) = _____ m
Related Questions
A train travels between stations 1 and 2. The engineer of the train is instructed to start from rest...
A car starts from rest and accelerate uniformly until it reaches a speed of 30m/s after 15s. It then...
A car starts from rest and accelerate uniformly until it reaches a speed of 30m/s after 15s. It then...