Asked by Anonymous
Starting from rest, a car accelerates at 2.5 m/s^2 up a hill that is inclined 5.4 ^\circ above the horizontal.
how far the car travel horizontally in 15s?
how far the car travel horizontally in 15s?
Answers
Answered by
Henry
I'm assuming the angle of inclination is 5.4 deg.
a(h) = 2.5m/s^2 * cos5.4 = 2.49m/s^2 =
hor. component of acceleration.
d = Vo*t + 0.5at^2,
d = 0 + 0.5*2.49*(15)^2 = 280m.
a(h) = 2.5m/s^2 * cos5.4 = 2.49m/s^2 =
hor. component of acceleration.
d = Vo*t + 0.5at^2,
d = 0 + 0.5*2.49*(15)^2 = 280m.
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