What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?

Answer 1

CuCl2 + 2NaNO3 ==> 2NaCl + Cu(NO3)2
mols CuCl2 = grams/molar mass
Using the coefficients in the balancaed equation,convert mols CuCl2 to mols NaCl formed.
Convert mols NaCl formed to grams. g = mols x molar mass. This is the theoretical yield (TY). The acuual yield (AY) is 2.12 g.

%yield = (AY/TY)*100 = ?

Answer 2

95.4