1.87 g Al = ?? moles.
moles = 1.87/molar mass Al.
Using the coefficients in the balanced equation, convert moles Al to moles Cu.
Now convert moles Cu to grams. g = moles x molar mass Cu. This is the theoretical yield of the reaction.
%yield = (actual yield/theoretical yield)*100 = ??
The actual yield is given in the problem as 4.65 grams.
What is the percent yield if 4.65g of copper is produced when 1.87g of aluminum reacts with an excess of copper(II) sulfate?
2Al(s)+3CuSO4(aq)==>Al2(SO4)3(aq)+3Cu(s)
1 answer
1 answer