Asked by Raj
Copper dissolves in nitric acid, producing copper (ll) nitrate. After reaction with sodium hydroxide and heating, copper nitrate changes to copper (ll) oxide. Calculate the percent yield of this process if 1.235 g of copper produced 1.452 g of copper oxide.
Answers
Answered by
DrBob222
Convert 1.235 g Cu to mols Cu.
Convert mols Cu to mols Cu(II) nitrate and to mols Cu(II) oxide.
Convert mols Cu(II) oxide to grams Cu(II) oxide. This is the theoretical yield in grams.
Then % yield = (1.452 g/theoretical yield)*100 =
Convert mols Cu to mols Cu(II) nitrate and to mols Cu(II) oxide.
Convert mols Cu(II) oxide to grams Cu(II) oxide. This is the theoretical yield in grams.
Then % yield = (1.452 g/theoretical yield)*100 =
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