Question

Given a percent yield of 45.0% for the reaction:
H2 + Cl2 → 2 HCl(g)
How many moles of HCl gas are produced
if 15.5 L of Cl2 at STP and excess H2 are
reacted?
1. 0.769 mol
2. 0.346 mol
3. 0.622 mol
4. 3.08 mol
5. 1.38 mol
6. 0.156 mol

Answer 1

With gases you may use a shortcut in which L are used directly as mols.

L H2 @ STP and 100% yield = 15.5L Cl2 x (2 mols HCl/1 mol Cl2) = 31 L H2O at 100%. At 45% it is 31 x 0.45 = ? L HCl

Answer 2

0.98

Answer 3

b nh

Answer 4

0.622 mol