Question
Given a percent yield of 45.0% for the reaction:
H2 + Cl2 → 2 HCl(g)
How many moles of HCl gas are produced
if 15.5 L of Cl2 at STP and excess H2 are
reacted?
1. 0.769 mol
2. 0.346 mol
3. 0.622 mol
4. 3.08 mol
5. 1.38 mol
6. 0.156 mol
H2 + Cl2 → 2 HCl(g)
How many moles of HCl gas are produced
if 15.5 L of Cl2 at STP and excess H2 are
reacted?
1. 0.769 mol
2. 0.346 mol
3. 0.622 mol
4. 3.08 mol
5. 1.38 mol
6. 0.156 mol
Answers
DrBob222
With gases you may use a shortcut in which L are used directly as mols.
L H2 @ STP and 100% yield = 15.5L Cl2 x (2 mols HCl/1 mol Cl2) = 31 L H2O at 100%. At 45% it is 31 x 0.45 = ? L HCl
L H2 @ STP and 100% yield = 15.5L Cl2 x (2 mols HCl/1 mol Cl2) = 31 L H2O at 100%. At 45% it is 31 x 0.45 = ? L HCl
Anonymous
0.98
Anonymous
b nh
idk
0.622 mol