Question
A ball thrown straight up at ground level
passes a height of 115.7 m in 5.6 s.
The acceleration of gravity is 9.8 m/s^2. What was its initial speed?
Answer in units of m/s.
passes a height of 115.7 m in 5.6 s.
The acceleration of gravity is 9.8 m/s^2. What was its initial speed?
Answer in units of m/s.
Answers
Henry
h = Vo*t + 0.5g*t^2 = 115.7 m
Vo*5.6 - 4.9*5.6^2 = 115.7
Vo*5.6 = 115.7+153.7 = 269.4
Vo = 48.1 m/s.
Vo*5.6 - 4.9*5.6^2 = 115.7
Vo*5.6 = 115.7+153.7 = 269.4
Vo = 48.1 m/s.