Asked by Barry
A ball was thrown straight up at 26.2 m/s then caught at the same place it was released. How many seconds was it in the air?
Answers
Answered by
bobpursley
hf=hi+vivertical*t-4.9t^2
0=0+26.2t-4.9t^2 solve for time in air, t
0=0+26.2t-4.9t^2 solve for time in air, t
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