Asked by Justin
f(x)=4sinx/1+cosx
find f'(x)
this is what i got and i dunno what i did to get it wrong
(4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62
Answers
Answered by
Reiny
looks like a ± error, and your denominator is wrong
my first line of the derivative was
(1+cosx)(4cosx) - 4sinx(-sinx))/(1+cosx)^2 using the quotient rule
expanding :
(4cosx + 4cos^2x + 4sin^2x)/(1+cosx)^2
= 4(cosx + 1)/(1+cosx)^2 , remember sin^2x+cos^2 = 1
= 4/(1+cosx)
my first line of the derivative was
(1+cosx)(4cosx) - 4sinx(-sinx))/(1+cosx)^2 using the quotient rule
expanding :
(4cosx + 4cos^2x + 4sin^2x)/(1+cosx)^2
= 4(cosx + 1)/(1+cosx)^2 , remember sin^2x+cos^2 = 1
= 4/(1+cosx)
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