Asked by Sarah

If siny=cosx, then find dy/dx at the point (pi/2, pi)
A. -1
B. 0
C. 1
D. pi/2
E. None of these

I got C
Answered by Steve
siny = cosx
cosy y' = -sinx
-y' = -1
C is correct
Answered by Samarth
-1
Siny=cosx
Y=sin'cosx
Y=sin'sinpi/2-x
Y=pi/2-x
Y'=0-1=-1
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